(5-3y)^2+y^2=25

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Solution for (5-3y)^2+y^2=25 equation: 



(5-3y)^2+y^2=25

We move all terms to the left:

(5-3y)^2+y^2-(25)=0

We add all the numbers together, and all the variables

y^2+(-3y+5)^2-25=0

We move all terms containing y to the left, all other terms to the right

y^2+(-3y+5)^2=25

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